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11x^2-29x+12=0
a = 11; b = -29; c = +12;
Δ = b2-4ac
Δ = -292-4·11·12
Δ = 313
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-\sqrt{313}}{2*11}=\frac{29-\sqrt{313}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+\sqrt{313}}{2*11}=\frac{29+\sqrt{313}}{22} $
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